What happens when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
class complex{
double re;
double im;
public:
complex() : re(1),im(0.4) {}
bool operator==(complex &t);
};
bool complex::operator == (complex &t){
if((this?>re == t.re) && (this?>im == t.im))
return true;
else
return false;
}
int main(){
complex c1,c2;
if (c1==c2)
cout << "OK";
else {
cout << "ERROR";
}
}
What is the output of the program if character 4 is supplied as input?
#include <iostream>
using namespace std;
int main () {
int c;
cin >> c;
try
{
switch (c)
{
case 1:
throw 20;
case 2:
throw 5.2f;
case 3:
throw 'a';
default:
cout<<"No exception";
}
}
catch (int e)
{ cout << "int exception. Exception Nr. " << e; }
catch (float e)
{ cout << "float exception. Exception Nr. " << e; }
catch (...)
{ cout << "An exception occurred."; }
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
class Base
{
string s;
public:
Base() { s="Sample text";}
Base(string s) { this?>s=s; }
void Print() { cout << s; }
};
int main()
{
Base *o = new Base();
o?>Print();
}
Given:
#include <iostream>
#include
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{
cout << "Error allocating memory";
}
catch (exception& e)
{
cout << "Standard exception";
}
catch (...)
{
cout << "Unknown exception";
}
return 0;
}
What will happen if we use the operator “new” and the memory cannot be allocated?
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int *i;
i = new int;
*i = 1.0 / 2 * 2 / 1 * 2 / 4 * 4;
cout << *i;
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
class A {
public:
int x;
A() { x=0;}
A(int x) { this?>x=x;}
};
class B : private A {
public:
using A::x;
B() { x=1;}
B(int x) {this?>x = x;}
};
int main () {
B c1;
B c2(?5);
cout << c1.x;
cout << c2.x;
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
void fun(char*);
int main()
{
char t[4]={'0', '1', '2', '3'};
fun(&t[2]);
return 0;
}
void fun(char *a)
{
cout << *a;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class BaseC
{
int *ptr;
public:
BaseC() { ptr = new int(10);}
BaseC(int i) { ptr = new int(i); }
~BaseC() { delete ptr; }
void Print() { cout << *ptr; }
};
int main()
{
BaseC *o = new BaseC(5);
o?>Print();
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x=20;
int *ptr;
ptr = &x;
cout<<*ptr;
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define FUN(arg) if(arg) cout<<"Test";
int main()
{
int i=1;
FUN(i<3);
return 0;
}
What is the output of the program if character 2 is supplied as input?
#include <iostream>
using namespace std;
int main () {
int c;
cin >> c;
try
{
switch (c)
{
case 1:
throw 20;
case 2:
throw 5.2f;
}
}
catch (int e)
{ cout << "int exception. Exception Nr. " << e; }
catch (float e)
{ cout << "float exception. Exception Nr. " << e; }
catch (...)
{ cout << "An exception occurred."; }
return 0;
}
Which of the following is a user defined data type?
1:
struct person
{
char name[20];
int age;
};
2:
int l=2;
3:
enum color {red,blue, green};
D.
char c;
What happens when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
};
class B : private A {
string name;
public:
void set() {
x = 1;
}
void Print() {
cout << x;
}
};
int main () {
B b;
b.set();
b.Print();
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
A() { x=1; y=2; z=3; }
};
class B : public A {
string z;
public:
void set() { y = 4; z = "John"; }
void Print() { cout << y << A::z; }
};
int main () {
B b;
b.set();
b.Print();
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int i = 4;
while(i >= 0) {
cout<<i;
i??;
}
return 0;
}
What will happen when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
string fun(string, string);
int main()
{
string s="Hello";
cout << fun(s, " World");
return 0;
}
string fun(string s1, string s2)
{
return s1+s2;
}
What is the output of the program?
#include <iostream>
#include
using namespace std;
int main()
{
string s1[]= {"H" , "t" };
string s;
for (int i=0; i<2; i++) {
s = s1[i];
if (i==0)
s.insert(1,"ow");
else
s.push_back('o');
cout << s;
}
return( 0 );
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
namespace myNamespace1
{
int x = 5;
int y = 10;
}
namespace myNamespace2
{
float x = 3.14;
float y = 1.5;
}
int main () {
namespace newname = myNamespace1;
using namespace newname;
cout << x << " ";
cout << y;
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int fun(int x) {
return 2*x;
}
int main(){
int i;
i = fun(1) || fun(2);
cout << i;
return 0;
}
What will happen when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define A 1
int main()
{
#if A
cout<<"Hello";
#endif
cout<<"world";
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int i = 1;
if (i++==1) {
cout << i;
} else {
cout << i-1;
}
return 0;
}
Which code, inserted at line 10, generates the output "2?1"?
#include <iostream>
#include
using namespace std;
class A {
protected:
int y;
public:
int z;
};
//insert code here
public:
void set() {
y = 2;
z = 3;
}
void Print() { cout << y << z; }
};
int main () {
B b;
b.set();
b.z = ?1;
b.Print();
return 0;
}
What is the output of the program if character 3 is supplied as input?
#include <iostream>
using namespace std;
int main () {
int c;
cin >> c;
try
{
switch (c)
{
case 1:
throw 20;
case 2:
throw 5.2f;
case 3:
throw 'a';
}
}
catch (int e)
{ cout << "int exception. Exception Nr. " << e; }
catch (float e)
{ cout << "float exception. Exception Nr. " << e; }
catch (...)
{ cout << "An exception occurred."; }
return 0;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int s(int n);
int main()
{
int a;
a = 3;
cout << s(a);
return 0;
}
int s(int n)
{
if(n == 0) return 1;
return s(n?1)*n;
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class First
{
public:
void Print(){ cout<<"from First";}
};
class Second
{
public:
void Print(){ cout<< "from Second";}
};
int main()
{
First FirstObject;
FirstObject.Print();
Second SecondObject;
SecondObject.Print();
}
What happens when you attempt to compile and run the following code?
#include <iostream>
#include
using namespace std;
class A {
int x;
protected:
int y;
public:
int z;
};
class B : public A {
string name;
public:
void set() {
y = 2;
z = 3;
}
void Print() { cout << y << z; }
};
int main () {
B b;
b.set();
b.Print();
return 0;
}
What is the output of the program if characters 't', 'e', 's' and 't' enter are supplied as input?
#include <iostream>
#include
using namespace std;
int main()
{
string s;
getline( cin, s );
cout << s << " " << s.length();
return( 0 );
}
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int fun(int x) {
return 2*x;
}
int main(){
int i;
i = fun(1) & fun(0);
cout << i;
return 0;
}